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CTET December 2019 » CBSE CTET December Apply Online

By Rajesh Antil - September 19, 2019

CBSE LogoCTET December 2019 Online Application: Central Board of Secondary Education (CBSE) has issued a latest notification for the recruitment of (CTET) Central Teacher Eligibility Test December 2019. Interested candidates can apply by 18 September 2019 (Extended Date 25/09/2019). Other details of CTET December 2019 Application Form, CBSE CTET December Exam Online Form 2019, Central Teacher Eligibility Test (CTET) December 2019, CTET December 2019 Notification, CTET December 2019, CTET December 2019 Online Application 2019, CTET Dec 2019, CTET Online Application Form 2019 Like Age Limit, Educational Qualification, Selection Process, Application Fee and How to Apply are given below…

CTET December 2019 @Online Application Central Teacher Eligibility Test

CBEC Online Applications for Teacher Eligibility Test CTET December 2019 Examination. CTET Recruitment 2019 for Central Teacher Eligibility Test (CTET) December 2019. CTET Application Form 2019. You can apply online in CTET December 2019 from 18 September 2019. (Extended Date 25/09/2019).

CBSE CTET December Exam Online Form 2019. Central Board of Secondary Education (CBSE) Read full Notification Before apply Online Registration. CTET Dec 2019 Notification/ Advertising short description below there:–

CBEC Central Teacher Eligibility Test 2019
CTET December 2019

Educational Qualifications

  • Candidates should have passed 12th Class, Graduate, Diploma.
  • Other education qualification details please go to the official notification.
Age Limit

  • Candidates age limit should be Minimum 18 years & Maximum 30 years.
  • The age relaxation for reserved category applicants is admissible only in the case of vacancies being reserved for such categories. The reserved category applicants, who apply against unreserved vacancies, will get age relaxation to the extent it is available to UR category candidates.
  • Age Relaxation: – SC/ ST /OBC/PWD/ PH Candidates Relaxation as per Government Rule Regulation.
CBSE CTET December Exam Online Form 2019
Central Board of Secondary Education Notification 2019
CTET December 2019
CBEC  CTET December 2019 Application Form Central Teacher Eligibility Test
Important Dates

  • Starting Date for Submission of Application: 19 August 2019.
  • Last Date for Submission of Application: 18 September 2019. (Extended Date 25/09/2019).
  • Last date for submission of fee: 30 September 2019 (Before 15:30 Hrs).
  • Online Correction: 27 September 2019 to 3 October 2019.
  • Admit Card Available: November Third Week 2019.

Exam Date Details

  • Date of Examination: 8 December 2019 (Sunday).
  • PAPER-I: 8 December 2019 (Sunday) 9:30 AM to 12.00 Noon 2:30 hour
  •  PAPER-II: 18 December 2019 (Sunday) 2:00 PM to 04:30 PM 2:30 hour.
Pay Details

  • Candidates should go to the notification given below for pay scale details.
Fees Details

  • For General/OBC application fee Only paper 1 & 2 Rs.700/-.
  • For General/OBC application fee Both paper 1 & 2 Rs.1200/-.
  • For SC/ST/Differently able person only paper 1 & 2 Rs.350/-.
  • For SC/ST/Differently able Person Rs. 600/-
How To Apply

  • Mode of Apply:- Through Online.
  • Job Location: All India.
  • Eligible candidates can apply through from official website 19 August 2019 or at Click on the below How to Apply links.
Selection Process

  • Candidates will be selected based on the Paper I & II.
  • There will be negative marking of 0.50 marks for each wrong answer.
Notification / Advertising

There is the full notification for Central Board of Secondary Education (CBSE) – Central Teacher Eligibility Test December 2019 (CTET 2019) Vacancy

How to Apply / New Registration

For Central Board of Secondary Education (CBSE) – Central Teacher Eligibility Test December 2019 (CTET 2019) Apply Online or New Registration from here –

Admit Card / Answer Key / Result

For Central Board of Secondary Education (CBSE) – Central Teacher Eligibility Test December 2019 (CTET 2019) you can take a print out of your Admit Card or Result from here-

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